A Cloudera certification unlocks career development that stays locked without it. The Cloudera CCA Spark and Hadoop Developer exam is the key, and the 96 practice questions at Prep4sureGuide are cut to fit it.
| Section | Objectives |
|---|---|
| Topic 1: Data Storage and File Systems | - HDFS fundamentals
|
| Topic 2: Data Ingestion and ETL | - Data transformation
|
| Topic 3: Data Analysis with Hive and Impala | - Hive querying
|
| Topic 4: Data Processing with Apache Spark | - Spark core operations
|
Cloudera CCA Spark and Hadoop Developer is an official Cloudera certification exam, registered under the code CCA175. Passing it awards the Cloudera Certified Associate (CCA) certification, a credential at the Associate level. It also connects to Cloudera Certified Associate (CCA) Administrator, Cloudera Data Platform Certifications. The exam is demanding by design, and that difficulty is precisely what makes the credential meaningful for career development.
The Cloudera CCA Spark and Hadoop Developer exam presents 12-15 performance-based tasks questions within 120 minutes. That is a brisk pace, and the candidates who handle it best are the ones who rehearsed it. Use the Prep4sureGuide engine for full timed simulations, practice flagging and returning, and arrive on exam day with a pacing strategy already proven.
Passing Cloudera CCA Spark and Hadoop Developer takes 70%, and official registration costs $295 USD. Retakes bill the full $295 USD again, so preparation is the least expensive insurance available. Let your Prep4sureGuide practice scores guide the timing: book when you clear the requirement consistently, not occasionally.
No strict prerequisites, but strong familiarity with Hadoop ecosystem, SQL, and programming in Python or Scala is recommended.
Policies get revised, so confirm the current requirements before you register on the official exam page.
Cloudera CCA Spark and Hadoop Developer registration is handled through the official channels below.
For scheduling purposes: the exam is delivered Online proctored, performance-based lab exam.
Yes, Cloudera recommends the following training for Cloudera CCA Spark and Hadoop Developer candidates.
Complement any training with the 96 practice questions in the Prep4sureGuide CCA175 package, because repeated application is what turns course knowledge into a passing score.
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Your money is protected by a 100% money-back guarantee with defined conditions. Take the Cloudera CCA Spark and Hadoop Developer exam within 60 days of purchase; if you fail, you may claim a full refund, provided the exam matches your product. Attempts within 3 days of purchase are ineligible, as are downloaded-but-unused products, free materials, and expired orders; the candidate name must match the payer name. Submit a scanned enrollment slip and the official Score Report PDF within 2 days of the exam, and claims are processed within 7 days. You may instead wait for the update version or change to other exam material: exchange for two other exam products of equal value, free, with your original purchase keeping its update service.
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Cloudera CCA Spark and Hadoop Developer is organized into 4 official domains. The most heavily weighted are Data Storage and File Systems, Data Processing with Apache Spark, and Data Analysis with Hive and Impala. The full breakdown appears above on this page; study the weightings and your preparation priorities set themselves.
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Problem Scenario 83 : In Continuation of previous question, please accomplish following activities.
1. Select all the records with quantity >= 5000 and name starts with 'Pen'
2. Select all the records with quantity >= 5000, price is less than 1.24 and name starts with
'Pen'
3. Select all the records witch does not have quantity >= 5000 and name does not starts with 'Pen'
4. Select all the products which name is 'Pen Red', 'Pen Black'
5. Select all the products which has price BETWEEN 1.0 AND 2.0 AND quantity
BETWEEN 1000 AND 2000.
Correct Answer:
See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1 : Select all the records with quantity >= 5000 and name starts with 'Pen' val results = sqlContext.sql(......SELECT * FROM products WHERE quantity >= 5000 AND name LIKE 'Pen %.......) results.show()
Step 2 : Select all the records with quantity >= 5000 , price is less than 1.24 and name starts with 'Pen' val results = sqlContext.sql(......SELECT * FROM products WHERE quantity >= 5000 AND price < 1.24 AND name LIKE 'Pen %.......) results. showQ
Step 3 : Select all the records witch does not have quantity >= 5000 and name does not starts with 'Pen' val results = sqlContext.sql('.....SELECT * FROM products WHERE NOT (quantity >= 5000
AND name LIKE 'Pen %')......)
results. showQ
Step 4 : Select all the products wchich name is 'Pen Red', 'Pen Black'
val results = sqlContext.sql('.....SELECT' FROM products WHERE name IN ('Pen Red',
'Pen Black')......)
results. showQ
Step 5 : Select all the products which has price BETWEEN 1.0 AND 2.0 AND quantity
BETWEEN 1000 AND 2000.
val results = sqlContext.sql(......SELECT * FROM products WHERE (price BETWEEN 1.0
AND 2.0) AND (quantity BETWEEN 1000 AND 2000)......)
results. show()
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Problem Scenario 88 : You have been given below three files
product.csv (Create this file in hdfs)
productID,productCode,name,quantity,price,supplierid
1001,PEN,Pen Red,5000,1.23,501
1002,PEN,Pen Blue,8000,1.25,501
1003,PEN,Pen Black,2000,1.25,501
1004,PEC,Pencil 2B,10000,0.48,502
1005,PEC,Pencil 2H,8000,0.49,502
1006,PEC,Pencil HB,0,9999.99,502
2001,PEC,Pencil 3B,500,0.52,501
2002,PEC,Pencil 4B,200,0.62,501
2003,PEC,Pencil 5B,100,0.73,501
2004,PEC,Pencil 6B,500,0.47,502
supplier.csv
supplierid,name,phone
501,ABC Traders,88881111
502,XYZ Company,88882222
503,QQ Corp,88883333
products_suppliers.csv
productID,supplierID
2001,501
2002,501
2003,501
2004,502
2001,503
Now accomplish all the queries given in solution.
1. It is possible that, same product can be supplied by multiple supplier. Now find each product, its price according to each supplier.
2. Find all the supllier name, who are supplying 'Pencil 3B'
3. Find all the products , which are supplied by ABC Traders.
Correct Answer:
See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1 : It is possible that, same product can be supplied by multiple supplier. Now find each product, its price according to each supplier.
val results = sqlContext.sql(......SELECT products.name AS Product Name', price, suppliers.name AS Supplier Name'
FROM products_suppliers
JOIN products ON products_suppliers.productlD = products.productID JOIN suppliers ON products_suppliers.supplierlD = suppliers.supplierlD null t results.show()
Step 2 : Find all the supllier name, who are supplying 'Pencil 3B'
val results = sqlContext.sql(......SELECT p.name AS 'Product Name", s.name AS "Supplier
Name'
FROM products_suppliers AS ps
JOIN products AS p ON ps.productID = p.productID
JOIN suppliers AS s ON ps.supplierlD = s.supplierlD
WHERE p.name = 'Pencil 3B"",M )
results.show()
Step 3 : Find all the products , which are supplied by ABC Traders.
val results = sqlContext.sql(......SELECT p.name AS 'Product Name", s.name AS "Supplier
Name'
FROM products AS p, products_suppliers AS ps, suppliers AS s WHERE p.productID = ps.productID AND ps.supplierlD = s.supplierlD
AND s.name = 'ABC Traders".....)
results. show()
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Problem Scenario 87 : You have been given below three files
product.csv (Create this file in hdfs)
productID,productCode,name,quantity,price,supplierid
1 001,PEN,Pen Red,5000,1.23,501
1 002,PEN,Pen Blue,8000,1.25,501
1003,PEN,Pen Black,2000,1.25,501
1004,PEC,Pencil 2B,10000,0.48,502
1005,PEC,Pencil 2H,8000,0.49,502
1006,PEC,Pencil HB,0,9999.99,502
2001,PEC,Pencil 3B,500,0.52,501
2002,PEC,Pencil 4B,200,0.62,501
2003,PEC,Pencil 5B,100,0.73,501
2004,PEC,Pencil 6B,500,0.47,502
supplier.csv
supplierid,name,phone
501,ABC Traders,88881111
502,XYZ Company,88882222
503,QQ Corp,88883333
products_suppliers.csv
productID,supplierID
2001,501
2002,501
2003,501
2004,502
2001,503
Now accomplish all the queries given in solution.
Select product, its price , its supplier name where product price is less than 0.6 using
SparkSQL
Correct Answer:
See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1:
hdfs dfs -mkdir sparksql2
hdfs dfs -put product.csv sparksq!2/
hdfs dfs -put supplier.csv sparksql2/
hdfs dfs -put products_suppliers.csv sparksql2/
Step 2 : Now in spark shell
// this Is used to Implicitly convert an RDD to a DataFrame.
import sqlContext.impIicits._
// Import Spark SQL data types and Row.
import org.apache.spark.sql._
// load the data into a new RDD
val products = sc.textFile("sparksql2/product.csv")
val supplier = sc.textFileC'sparksq^supplier.csv")
val prdsup = sc.textFile("sparksql2/products_suppliers.csv"}
// Return the first element in this RDD
products.fi rst()
supplier.first{).
prdsup.first()
//define the schema using a case class
case class Product(productid: Integer, code: String, name: String, quantity:lnteger, price:
Float, supplierid:lnteger)
case class Suplier(supplierid: Integer, name: String, phone: String)
case class PRDSUP(productid: Integer.supplierid: Integer)
// create an RDD of Product objects
val prdRDD = products.map(_.split('\")).map(p =>
Product(p(0).tolnt,p(1),p(2),p(3).tolnt,p(4).toFloat,p(5).toint))
val supRDD = supplier.map(_.split(",")).map(p => Suplier(p(0).tolnt,p(1),p(2))) val prdsupRDD = prdsup.map(_.split(",")).map(p => PRDSUP(p(0).tolnt,p(1}.tolnt}} prdRDD.first() prdRDD.count() supRDD.first() supRDD.count()
prdsupRDD.first() prdsupRDD.count(}
// change RDD of Product objects to a DataFrame
val prdDF = prdRDD.toDF()
val supDF = supRDD.toDF()
val prdsupDF = prdsupRDD.toDF()
// register the DataFrame as a temp table prdDF.registerTempTablef'products") supDF.registerTempTablef'suppliers") prdsupDF.registerTempTablef'productssuppliers"}
//Select product, its price , its supplier name where product price is less than 0.6 val results = sqlContext.sql(......SELECT products.name, price, suppliers.name as sup_name FROM products JOIN suppliers ON products.supplierlD= suppliers.supplierlD
WHERE price < 0.6......]
results. show()
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Problem Scenario 47 : You have been given below code snippet, with intermediate output.
val z = sc.parallelize(List(1,2,3,4,5,6), 2)
// lets first print out the contents of the RDD with partition labels
def myfunc(index: Int, iter: lterator[(lnt)]): lterator[String] = {
iter.toList.map(x => "[partID:" + index + ", val: " + x + "]").iterator
}
//In each run , output could be different, while solving problem assume belowm output only.
z.mapPartitionsWithlndex(myfunc).collect
res28: Array[String] = Array([partlD:0, val: 1], [partlD:0, val: 2], [partlD:0, val: 3], [partlD:1, val: 4], [partlD:1, val: S], [partlD:1, val: 6])
Now apply aggregate method on RDD z , with two reduce function , first will select max value in each partition and second will add all the maximum values from all partitions.
Initialize the aggregate with value 5. hence expected output will be 16.
Correct Answer:
z.aggregate(5)(math.max(_, J, _ + _)
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Problem Scenario 76 : You have been given MySQL DB with following details.
user=retail_dba
password=cloudera
database=retail_db
table=retail_db.orders
table=retail_db.order_items
jdbc URL = jdbc:mysql://quickstart:3306/retail_db
Columns of order table : (orderid , order_date , ordercustomerid, order_status}
.....
Please accomplish following activities.
1 . Copy "retail_db.orders" table to hdfs in a directory p91_orders.
2 . Once data is copied to hdfs, using pyspark calculate the number of order for each status.
3 . Use all the following methods to calculate the number of order for each status. (You need to know all these functions and its behavior for real exam)
- countByKey()
-groupByKey()
- reduceByKey()
-aggregateByKey()
- combineByKey()
Correct Answer:
See the explanation for Step by Step Solution and configuration.
Explanation:
Solution :
Step 1 : Import Single table
sqoop import --connect jdbc:mysql://quickstart:3306/retail_db --username=retail dba - password=cloudera -table=orders --target-dir=p91_orders
Note : Please check you dont have space between before or after '=' sign. Sqoop uses the
MapReduce framework to copy data from RDBMS to hdfs
Step 2 : Read the data from one of the partition, created using above command, hadoop fs
-cat p91_orders/part-m-00000
Step 3: countByKey #Number of orders by status allOrders = sc.textFile("p91_orders")
#Generate key and value pairs (key is order status and vale as an empty string keyValue = aIIOrders.map(lambda line: (line.split(",")[3], ""))
#Using countByKey, aggregate data based on status as a key
output=keyValue.countByKey()Jtems()
for line in output: print(line)
Step 4 : groupByKey
#Generate key and value pairs (key is order status and vale as an one
keyValue = allOrders.map(lambda line: (line.split)",")[3], 1))
#Using countByKey, aggregate data based on status as a key output=
keyValue.groupByKey().map(lambda kv: (kv[0], sum(kv[1]}}}
tor line in output.collect(): print(line}
Step 5 : reduceByKey
#Generate key and value pairs (key is order status and vale as an one
keyValue = allOrders.map(lambda line: (line.split(","}[3], 1))
#Using countByKey, aggregate data based on status as a key output=
keyValue.reduceByKey(lambda a, b: a + b)
tor line in output.collect(): print(line}
Step 6: aggregateByKey
#Generate key and value pairs (key is order status and vale as an one keyValue = allOrders.map(lambda line: (line.split(",")[3], line}} output=keyValue.aggregateByKey(0, lambda a, b: a+1, lambda a, b: a+b} for line in output.collect(): print(line}
Step 7 : combineByKey
#Generate key and value pairs (key is order status and vale as an one
keyValue = allOrders.map(lambda line: (line.split(",")[3], line))
output=keyValue.combineByKey(lambda value: 1, lambda ace, value: acc+1, lambda ace, value: acc+value) tor line in output.collect(): print(line)
#Watch Spark Professional Training provided by www.ABCTECH.com to understand more on each above functions. (These are very important functions for real exam)
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